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D and E are the mid-points of AB and AC of triangle ABC. The median AM (M mid-point of BC) intersects DE at point P.
What is the ratio in which DE divides the median AM, i.e. AP : PM?

Class 9The Mid-point TheoremGeometry — Quadrilaterals
  • A1 : 1
  • B1 : 2
  • C2 : 1
  • D1 : 3

Step-by-Step Solution

DE is parallel to BC and passes through mid-points; by the converse it bisects AM, so AP : PM = 1 : 1.
Answer: A) 1 : 1

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