- A0.875 cm
- B1.75 cm
- C3.5 cm
- D0.4375 cm
Step-by-Step Solution
Each nested midsegment halves the previous: 7, 3.5, 1.75, 0.875. The 4th is 0.875 cm.
Answer: A) 0.875 cm
The midsegment DE of triangle ABC (joining mid-points of AB and AC) has length 7 cm. The midsegment of the upper triangle ADE (joining mid-points of AD and AE) is then drawn.
Continuing this halving pattern, what is the length of the 4th such nested midsegment, counting DE as the 1st?
Class 9The Mid-point TheoremGeometry — Quadrilaterals
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