In the figure, AD = BC and ∠DAB = ∠CBA = 75° (matching marks). Triangles ABD and BAC overlap and share the side AB. If ∠ABD = 35°, find ∠ACB.
Class 9Triangles (Congruence)Geometry — Triangles
A35°
B75°
C110°
D70°
Step-by-Step Solution
△ABD≅△BAC (SAS: AD=BC,∠DAB=∠CBA,AB common). By CPCT ∠BAC=∠ABD=35∘, so in △ABC,∠ACB=180∘−35∘−75∘=70∘.
Answer: D) 70°
Key idea: The four valid congruence criteria
**SSS**: All three sides equal → congruent.
**SAS**: Two sides + included angle equal → congruent. IMPORTANT: the angle must be BETWEEN the two given sides. SSA (two sides + non-included angle) is NOT a valid criterion in general.
**ASA**: Two angles + included side equal → congruent.
**AAS**: Two angles + a non-included side equal → congruent (since the third angle is forced by 180°).
**RHS** (right triangles only): Right angle + hypotenuse + one side equal → congruent.
**Once congruent, all corresponding parts are equal (CPCT)** — that's the lemma you cite to extract any matching side or angle in the next step of a proof.
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