A shopkeeper in Indore sells tea at Rs x per cup and coffee at Rs y per cup. On Monday he sold 10 cups of tea and 5 cups of coffee for Rs 250. On Tuesday he sold 5 cups of tea and 10 cups of coffee for Rs 350. Find the price of one cup of coffee (Rs y).

Question

Accepted Answer

30. 10x + 5y = 250 (i.e. 2x + y = 50) and 5x + 10y = 350 (i.e. x + 2y = 70). From first y = 50 - 2x; substitute: x + 2(50 - 2x) = 70, x + 100 - 4x = 70, -3x = -30, x = 10, y = 30.

A shopkeeper in Indore sells tea at Rs $x$ per cup and coffee at Rs $y$ per cup. On Monday he sold 10 cups of tea and 5 cups of coffee for Rs 250. On Tuesday he sold 5 cups of tea and 10 cups of coffee for Rs 350.
Find the price of one cup of coffee (Rs $y$ ).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Word Problems practice

A shopkeeper in Indore sells tea at Rs x per cup and coffee at Rs y per cup. On Monday he sold 10 cups of tea and 5 cups of coffee for Rs 250. On Tuesday he sold 5 cups of tea and 10 cups of coffee for Rs 350.Find the price of one cup of coffee (Rs y).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 9 Word Problems practice

A shopkeeper in Indore sells tea at Rs $x$ per cup and coffee at Rs $y$ per cup. On Monday he sold 10 cups of tea and 5 cups of coffee for Rs 250. On Tuesday he sold 5 cups of tea and 10 cups of coffee for Rs 350.
Find the price of one cup of coffee (Rs $y$ ).