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For what positive value of $p$ does the equation $2 x^{2} + p x + 8 = 0$ have two equal real roots?

Competition practiceAlgebra

A8
B4
C16
D64

Step-by-Step Solution

Equal roots need

p^{2} - 4 \times 2 \times 8 = 0

, so

p^{2} = 64

and

p = 8

(taking the positive value).

Answer: A) 8

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