If a + b + c = 0 and abc = 5, then a³ + b³ + c³ equals:

Question

Accepted Answer

15. The identity a³ + b³ + c³ − 3abc = (a + b + c)(a² + b² + c² − ab − bc − ca) gives 0 on the right when a + b + c = 0. So a³ + b³ + c³ = 3abc = 3 × 5 = 15.

If $a + b + c = 0$ and $ab c = 5$ , then $a^{3} + b^{3} + c^{3}$ equals:

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If a+b+c=0 and abc=5, then a3+b3+c3 equals:

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If $a + b + c = 0$ and $ab c = 5$ , then $a^{3} + b^{3} + c^{3}$ equals: