A2n2Bn(n+1)/2Cn2Dn2+n Step-by-Step SolutionS₇ = 7/2[2a+6d]=7(a+3d)=49 gives a+3d=7, and S₁₇ = 17(a+8d)=289 gives a+8d=17. Subtracting, 5d=10, so d=2 and a=1. Then Sₙ = n/2[2+2(n−1)]=n2.Answer: C) n2