Solved by the cross-multiplication method, the pair $3x-5y-4=0$ and $9x=2y+7$ gives:

Rewrite the second equation as $9x-2y-7=0$. With a₁ = 3, b₁ = −5, c₁ = −4 and a₂ = 9, b₂ = −2, c₂ = −7 the rule $x$/(b₁c₂ − b₂c₁) = $y$/(c₁a₂ − c₂a₁) = 1/(a₁b₂ − a₂b₁) gives $x/(35-8)=y/(-36+21)=1/(-6+45)$, i.e. $x/27=y/(-15)=1/39$. Hence $x=27/39=9/13$ and $y=-15/39=-5/13$. (Dropping the minus sign in the $y$ numerator gives the first option.) Check: $3(9/13)+25/13=52/13=4$.