The HCF of two polynomials is (x + 3) and their LCM is (x − 2)(x + 3)(x + 4). If one of them is x² + x − 6, the other is:

Question

Accepted Answer

x² + 7x + 12. The product of the two polynomials equals HCF × LCM. Since x² + x − 6 = (x + 3)(x − 2), the other polynomial is (x + 3)(x − 2)(x + 3)(x + 4) ÷ [(x + 3)(x − 2)] = (x + 3)(x + 4) = x² + 7x + 12. Its HCF with (x + 3)(x − 2) is indeed (x + 3).

The HCF of two polynomials is $(x + 3)$ and their LCM is $(x - 2) (x + 3) (x + 4)$ . If one of them is $x^{2} + x - 6$ , the other is:

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The HCF of two polynomials is (x+3) and their LCM is (x−2)(x+3)(x+4). If one of them is x2+x−6, the other is:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

The HCF of two polynomials is $(x + 3)$ and their LCM is $(x - 2) (x + 3) (x + 4)$ . If one of them is $x^{2} + x - 6$ , the other is: