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The least value taken by the expression $x^{2} - 6 x + 13$ is:

Competition practiceAlgebra

A3
B4
C13
D−4

Step-by-Step Solution

Complete the square:

x^{2} - 6 x + 13 = (x - 3)^{2} + 4

. Since

(x - 3)^{2}

is never negative, the smallest value is 4, reached at

x = 3

.

Answer: B) 4

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