The pair of equations 2x + 3y = 5 and 4x + ky = 10 has infinitely many solutions when k equals:

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Accepted Answer

6. Infinitely many solutions need a₁/a₂ = b₁/b₂ = c₁/c₂. Here 2/4 = 1/2 and 5/10 = 1/2, so 3/k = 1/2 gives k = 6 (the second equation is then just twice the first).

The pair of equations $2 x + 3 y = 5$ and $4 x + k y = 10$ has infinitely many solutions when $k$ equals:

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The pair of equations 2x+3y=5 and 4x+ky=10 has infinitely many solutions when k equals:

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Algebra practice

The pair of equations $2 x + 3 y = 5$ and $4 x + k y = 10$ has infinitely many solutions when $k$ equals: