A bucket open at the top is a frustum 24 cm deep whose top radius is 28 cm and whose base radius is 21 cm. Find the area of metal sheet used to make it — its sloping side together with its closed base — in cm². Take π = 22/7.

Question

Accepted Answer

5236. Slant height = √(24² + (28 − 21)²) = √(576 + 49) = √625 = 25 cm. Sloping surface = πl(R + r) = (22/7) × 25 × 49 = 3850 cm². Base = πr² = (22/7) × 441 = 1386 cm². Metal = 3850 + 1386 = 5236 cm². (Stopping at 3850 forgets the base; adding the top circle 2464 cm² as well gives 7700, but the bucket is open; using the top circle instead of the base gives 6314.)

A bucket open at the top is a frustum 24 cm deep whose top radius is 28 cm and whose base radius is 21 cm. Find the area of metal sheet used to make it — its sloping side together with its closed base — in $cm^{2}$ . Take π = 22/7.

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More Areas & Volumes practice

A bucket open at the top is a frustum 24 cm deep whose top radius is 28 cm and whose base radius is 21 cm. Find the area of metal sheet used to make it — its sloping side together with its closed base — in cm2. Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A bucket open at the top is a frustum 24 cm deep whose top radius is 28 cm and whose base radius is 21 cm. Find the area of metal sheet used to make it — its sloping side together with its closed base — in $cm^{2}$ . Take π = 22/7.