A cubical block of wood of edge 10 cm and mass 600 g floats in water. A floating body sinks until the water it pushes aside weighs exactly as much as the body, and 1 cm³ of water weighs 1 g. Find the volume of the block that lies below the water surface, in cm³.

Question

Accepted Answer

600. The water pushed aside must weigh 600 g, and since 1 cm³ of water weighs 1 g, that water occupies 600 cm³. So 600 cm³ of the block is submerged (the block's full volume is 1000 cm³, so 400 cm³ stands above the surface).

A cubical block of wood of edge 10 cm and mass 600 g floats in water. A floating body sinks until the water it pushes aside weighs exactly as much as the body, and $1 cm^{3}$ of water weighs 1 g. Find the volume of the block that lies below the water surface, in $cm^{3}$ .

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More Areas & Volumes practice

A cubical block of wood of edge 10 cm and mass 600 g floats in water. A floating body sinks until the water it pushes aside weighs exactly as much as the body, and 1cm3 of water weighs 1 g. Find the volume of the block that lies below the water surface, in cm3.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A cubical block of wood of edge 10 cm and mass 600 g floats in water. A floating body sinks until the water it pushes aside weighs exactly as much as the body, and $1 cm^{3}$ of water weighs 1 g. Find the volume of the block that lies below the water surface, in $cm^{3}$ .