A hall is supported by 12 identical cylindrical pillars, each of diameter 0.7 m and height 5 m. Only the curved surface of each pillar is to be painted, at ₹25 per m². Find the total cost in rupees. Take π = 22/7.

Question

Accepted Answer

3300. Curved surface of one pillar = πdh = (22/7) × 0.7 × 5 = 11 m². For 12 pillars that is 132 m². Cost = 132 × 25 = ₹3300. (The flat circular ends are not painted; including them would wrongly raise the bill.)

A hall is supported by 12 identical cylindrical pillars, each of diameter 0.7 $m$ and height 5 $m$ . Only the curved surface of each pillar is to be painted, at ₹25 per $m^{2}$ . Find the total cost in rupees. Take π = 22/7.

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A hall is supported by 12 identical cylindrical pillars, each of diameter 0.7 m and height 5 m. Only the curved surface of each pillar is to be painted, at ₹25 per m2. Find the total cost in rupees. Take π = 22/7.

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More Areas & Volumes practice

A hall is supported by 12 identical cylindrical pillars, each of diameter 0.7 $m$ and height 5 $m$ . Only the curved surface of each pillar is to be painted, at ₹25 per $m^{2}$ . Find the total cost in rupees. Take π = 22/7.