A solid cone has base radius 14 cm and vertical height 12 cm. A plane parallel to the base cuts it through the midpoint of its axis. Find the volume of the frustum, the lower of the two pieces, in cm³. Take π = 22/7.

Question

Accepted Answer

2156. Whole cone = (1/3) × (22/7) × 196 × 12 = 2464 cm³. The small cone cut off has half the height, 6 cm, and half the radius, 7 cm, so its volume = (1/3) × (22/7) × 49 × 6 = 308 cm³. Frustum = 2464 − 308 = 2156 cm³.

A solid cone has base radius 14 cm and vertical height 12 cm. A plane parallel to the base cuts it through the midpoint of its axis. Find the volume of the frustum, the lower of the two pieces, in $cm^{3}$ . Take π = 22/7.

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A solid cone has base radius 14 cm and vertical height 12 cm. A plane parallel to the base cuts it through the midpoint of its axis. Find the volume of the frustum, the lower of the two pieces, in cm3. Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A solid cone has base radius 14 cm and vertical height 12 cm. A plane parallel to the base cuts it through the midpoint of its axis. Find the volume of the frustum, the lower of the two pieces, in $cm^{3}$ . Take π = 22/7.