A tent has a cylindrical lower part of radius 7 m and height 3 m, with a conical top of the same radius whose vertical height is 24 m. Find the area of canvas needed for the tent (the floor is not covered) in m². Take π = 22/7.

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Accepted Answer

682. The cone's slant height = √(24² + 7²) = √625 = 25 m, so its curved surface = (22/7) × 7 × 25 = 550 m². The cylinder's curved surface = 2 × (22/7) × 7 × 3 = 132 m². Canvas = 550 + 132 = 682 m².

A tent has a cylindrical lower part of radius 7 $m$ and height 3 $m$ , with a conical top of the same radius whose vertical height is 24 $m$ . Find the area of canvas needed for the tent (the floor is not covered) in $m^{2}$ . Take π = 22/7.

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A tent has a cylindrical lower part of radius 7 m and height 3 m, with a conical top of the same radius whose vertical height is 24 m. Find the area of canvas needed for the tent (the floor is not covered) in m2. Take π = 22/7.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Areas & Volumes practice

A tent has a cylindrical lower part of radius 7 $m$ and height 3 $m$ , with a conical top of the same radius whose vertical height is 24 $m$ . Find the area of canvas needed for the tent (the floor is not covered) in $m^{2}$ . Take π = 22/7.