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Two fair dice are thrown. What is the probability of getting at least one six?

Competition practiceData & Probability
  • A1/6
  • B1/3
  • C11/36
  • D25/36

Step-by-Step Solution

P(no six on either die) = (5/6) × (5/6) = 25/36. By the complement rule, P(at least one six) = 1 − 25/36 = 11/36.
Answer: C) 11/36

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