- A92°
- B100°
- C73°
- D46°
Step-by-Step Solution
A tangent and a secant meeting outside the circle behave exactly like two secants: the angle is half the difference of the far arc and the near arc. Here ∠TPA = ½(146° − 54°) = ½ × 92° = 46°. (The three arcs check out: 54° + 146° + arc AB = 360°, so arc AB = 160°.) The trap 92° stops at the difference without halving, 100° halves the sum instead of the difference, and 73° halves only the far arc.
Answer: D) 46°