From a point P outside a circle, a secant through P meets the circle first at A and then at B, with PA = 4 cm and AB = 5 cm. A tangent from P touches the circle at T. What is the length of PT?
Competition practiceGeometry
A4.5 cm
B7 cm
C6 cm
D8 cm
Step-by-Step Solution
PB=PA+AB=4+5=9 cm. By the tangent–secant relation, PT2=PA×PB=4×9=36, so PT=6 cm.
Answer: C) 6 cm
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