- A136°
- B16°
- C68°
- D42°
Step-by-Step Solution
When two chords cross INSIDE a circle, the angle between them is half the SUM of the two arcs they cut off — the arc between the two near ends and the arc between the two far ends. ∠APC stands on arc AC and on the vertically opposite arc BD, so ∠APC = ½(84° + 52°) = ½ × 136° = 68°. Forgetting to halve gives 136°; using half the DIFFERENCE, ½(84° − 52°) = 16°, applies the rule for a point OUTSIDE the circle; and 42° halves just one of the two arcs.
Answer: C) 68°