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The greatest number that divides 1657 and 2037 leaving remainders 6 and 5 respectively is:

Competition practiceNumber & Arithmetic
  • A13
  • B381
  • C127
  • D137

Step-by-Step Solution

Take away the remainders so the division becomes exact: 1657 − 6 = 1651 and 2037 − 5 = 2032. The required number is HCF(1651, 2032). Since and , and 13 and 16 share nothing, the HCF is 127 (comfortably larger than both remainders). Answering 381 confuses the HCF with the difference 2032 − 1651, and 13 is only the co-factor.
Answer: C) 127

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