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Given $x - y = 2$ and $y - z = 3$ , find $(x - y)^{3} + (y - z)^{3} + (z - x)^{3}$ .

Competition practiceAlgebra

A−90
B90
C35
D−125

Step-by-Step Solution

z - x = - 5

. The three differences add to 0, so the sum of cubes is

3 (2) (3) (- 5) = - 90

.

Answer: A) −90

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