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Real numbers satisfy $(x - 3)^{2} + (y - 4)^{2} + (z + 2)^{2} = 0$ . What is $x + y + z$ ?

Competition practiceAlgebra

A5
B9
C1
D−5

Step-by-Step Solution

A sum of squares is 0 only if each square is 0:

x = 3, y = 4, z = - 2

, so the sum is 5.

Answer: A) 5

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