AB is a diameter of a circle with centre O, and C is a point on the circle with ∠BOC = 64°. D is a point on the arc AC that does not contain B. Find ∠ADC.

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Accepted Answer

122°. ∠AOC = 180° - 64° = 116°, so arc AC (not containing B) is the minor arc. A point on the major arc would see AC at 58°; D lies on the minor arc, so ∠ADC = 180° - 58° = 122°.

AB is a diameter of a circle with centre O, and C is a point on the circle with ∠BOC = 64°. D is a point on the arc AC that does not contain B. Find ∠ADC.

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