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ABCD is a parallelogram with AB = 11 cm and AD = 7 cm. The bisector of ∠A meets DC at E. Find EC.

Competition practiceGeometry
  • A4 cm
  • B6 cm
  • C5 cm
  • D3 cm

Step-by-Step Solution

∠DEA = ∠EAB (alternate angles, AB ∥ DC) = ∠DAE, so triangle ADE is isosceles with DE = AD = 7 cm. Hence EC = DC − DE = 11 − 7 = 4 cm.
Answer: A) 4 cm

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