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An isosceles trapezium has parallel sides of 10 cm and 24 cm, and each non-parallel side is 25 cm. What is its area?

Competition practiceGeometry

A $408 cm^{2}$
B $425 cm^{2}$
C $816 cm^{2}$
D $391 cm^{2}$

Step-by-Step Solution

Each slant side overhangs by

\frac{24 - 10}{2} = 7

cm, so the height is

2 5^{2} - 7^{2} = 24

cm. Area

= \frac{1}{2} (10 + 24) \times 24 = 408 cm^{2}

.

Answer: A)

408 cm^{2}

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