Each side of a rhombus is 10 cm and its diagonals differ by 4 cm. What is its area?

Question

Accepted Answer

96 cm². With diagonals p and q: p^2 + q^2 = 4 × 10^2 = 400 and p − q = 4. Then (q + 4)^2 + q^2 = 400 gives q = 12 and p = 16, so the area is 1/2 × 16 × 12 = 96 cm².

Each side of a rhombus is 10 cm and its diagonals differ by 4 cm. What is its area?

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