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PA and PB are tangents to a circle from an external point P, and ∠APB = 70°. Find ∠PAB.

Competition practiceGeometry
  • A55°
  • B70°
  • C35°
  • D110°

Step-by-Step Solution

Tangents from an external point are equal, so triangle is isosceles and .
Answer: A) 55°

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