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What is the distance between the parallel lines $3 x + 4 y = 7$ and $6 x + 8 y = 39$ ?

Competition practiceGeometry

A2.5 units
B6.4 units
C3.2 units
D5 units

Step-by-Step Solution

Rewrite the second line as

3 x + 4 y = 19.5

so both have the same coefficients. Distance

= \frac{∣19.5 - 7∣}{3 ^{2} + 4 ^{2}} = \frac{12.5}{5} = 2.5

units.

Answer: A) 2.5 units

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