Practice30 Create account

Find the smallest number which, when increased by 17, is exactly divisible by both 520 and 468.

Competition practiceNumber System, HCF & LCM

A4663
B4697
C4680
D2323

Step-by-Step Solution

520 =

2^{3} \times 5 \times 13

and

468 = 2^{2} \times 3^{2} \times 13

, so LCM =

2^{3} \times 3^{2} \times 5 \times 13 = 4680

. The number is 4680 − 17 = 4663.

Answer: A) 4663

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Number System, HCF & LCM practice questions

More Number System, HCF & LCM practice

Two numbers add up to 100. Their HCF is 5 and their LCM is 495. By how much do they…Find the largest four-digit number that leaves remainder 3 on division by each of 4, 7…A number leaves remainders 1, 2, 3 and 4 when divided by 2, 3, 4 and 5 respectively.…Two numbers are in the ratio 4 : 5, and their LCM exceeds their HCF by 228. Find the sum…Add up all the natural numbers n for which LCM(n, 12) = 60. What is the total?