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Poles are to be fixed along the boundary of a rectangular field 252 m by 180 m, at equal distances as large as possible, with a pole at every corner. How many poles are needed?

Competition practiceNumber System, HCF & LCM
  • A24
  • B26
  • C12
  • D22

Step-by-Step Solution

Gap = HCF(252, 180) = 36 m. Along a closed boundary the number of poles equals the number of gaps: perimeter 864 m ÷ 36 = 24 poles.
Answer: A) 24

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