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A machine is set to fill 500 g packets, and a packet clears inspection only if its weight is within 3% of 500 g. A packet on the belt weighs 518 g. By how many grams does it exceed the heaviest weight allowed?

Competition practicePercentage
  • A18 g
  • B15 g
  • C0 g - the packet passes
  • D3 g

Step-by-Step Solution

The allowance is 3% of 500 = 15 g, so a packet may weigh anything from 485 g to 515 g. At 518 g it is over the top of that band by 518 - 515 = 3 g. 18 g measures the excess over the 500 g setting and forgets that a 15 g allowance exists. 15 g quotes the allowance itself. '0 g - the packet passes' is the trap of comparing 518 with 500 + 18 or of assuming 3% is generous; the band closes at 515 g.
Answer: D) 3 g

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