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Using the digits 0, 1, 2, 3, 4 and 5, with no digit repeated, how many 3-digit numbers divisible by 5 can be formed?

Competition practicePermutations & Combinations
  • A40
  • B20
  • C36
  • D48

Step-by-Step Solution

Ending in 0: the first two places take any 2 of 1–5 in order, . Ending in 5: first digit cannot be 0 or 5, 4 ways, then 4 ways for the middle: 16. Total .
Answer: C) 36

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