A colony committee has 9 members, of whom 3 are picked at random to attend a municipal meeting. What is the probability that one particular member, Anil, is among the three picked?

Total selections = C(9,3) = 84. Selections that include Anil are fixed on him plus any 2 of the other 8: C(8,2) = 28. Probability = 28/84 = 1/3. A quicker route: 3 of the 9 seats are filled and every member is equally likely to hold one, so the chance is 3/9 = 1/3. Trap 1/9 treats it as though only ONE member were being picked. Trap 2/3 is the chance Anil is left out. Trap 1/84 is the chance of one particular trio being picked.