- A10/21
- B5/42
- C1/21
- D5/9
Step-by-Step Solution
Total selections = C(9,3) = 84. All-boy selections = C(5,3) = 10. Probability = 10/84 = 5/42. (10/21 is the chance of exactly two boys, 1/21 the chance of all girls.)
Answer: B) 5/42
From a group of 5 boys and 4 girls, 3 students are selected at random for a quiz team. What is the probability that all three selected are boys?
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