- A15/34
- B19/34
- C1/4
- D7/17
Step-by-Step Solution
Total ways = C(52,2) = 1326. Neither card a spade: C(39,2) = 741, so P(no spade) = 741/1326 = 19/34. Hence P(at least one spade) = 1 - 19/34 = 15/34.
Answer: A) 15/34
Two cards are drawn at random together from a well-shuffled pack of 52 playing cards. What is the probability that at least one of them is a spade?
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