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After solving I. $x^{2} - 29 x + 210 = 0$
II. $y^{2} - 23 y + 130 = 0$ , how do $x$ and $y$ compare?

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x < y$
C $x$ ≥ $y$
D $x > y$

Step-by-Step Solution

I:

(x - 14) (x - 15) = 0

→

x = 14

, 15. II:

(y - 10) (y - 13) = 0

→

y = 10

, 13. Every

x

is larger, so

x > y

.

Answer: D)

x > y

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