Both equations have negative roots. Find them and compare $x$ with $y$ . I. $2 x^{2} + 15 x + 28 = 0$
II. $2 y^{2} + 11 y + 14 = 0$

Question

Both equations have negative roots. Find them and compare x with y. I. 2x² + 15x + 28 = 0 II. 2y² + 11y + 14 = 0

Accepted Answer

x ≤ y. I: (2x + 7)(x + 4) = 0 → x = −3.5, −4. II: (2y + 7)(y + 2) = 0 → y = −3.5, −2. The largest x equals the smallest y (−3.5), so x ≤ y.

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