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Compare the roots: I. $x^{2} = 64$
II. $y^{2} - 16 y + 64 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x > y$
C $x < y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

x = 8

or −8. II:

(y - 8)^{2} = 0

→

y = 8

. Both

x

-values are at most 8, so

x

≤

y

.

Answer: D)

x

≤

y

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