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Determine how $x$ and $y$ compare. I. $x^{2} - 4 x - 21 = 0$
II. $y^{2} + 7 y + 12 = 0$ .

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≤ $y$
C $x > y$
D $x$ ≥ $y$

Step-by-Step Solution

I:

(x - 7) (x + 3) = 0

→

x = 7

, −3. II:

(y + 3) (y + 4) = 0

→

y = - 3

, −4. The smallest

x

equals the largest

y

(−3), so

x

≥

y

.

Answer: D)

x

≥

y

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