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Solve the pair and pick the right relation between $x$ and $y$ . I. $x^{2} - 15 x + 50 = 0$
II. $y^{2} - 22 y + 120 = 0$

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x > y$
C $x < y$
D $x$ ≥ $y$

Step-by-Step Solution

x = 5

or 10;

y = 10

or 12.

x

never exceeds

y

and

x = y = 10

is possible, so

x

≤

y

.

Answer: A)

x

≤

y

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