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Determine the relation between $x$ and $y$ from: I. $2 x^{2} - 7 x + 6 = 0$
II. $y^{2} - 6 y + 9 = 0$

Competition practiceQuadratic Comparison

A $x > y$
B $x$ ≤ $y$
C $x < y$
D $x$ ≥ $y$

Step-by-Step Solution

I:

(2 x - 3) (x - 2) = 0

, so

x = 1.5

or 2. II:

(y - 3)^{2} = 0

, so

y = 3

. Both values of

x

are less than 3, so

x < y

.

Answer: C)

x < y

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