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Equation I: $x^{2} - 25 x + 156 = 0$ . Equation II: $y^{2} - 13 y + 40 = 0$ . What is the relation between $x$ and $y$ ?

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≤ $y$
C $x > y$
D $x$ ≥ $y$

Step-by-Step Solution

I:

(x - 12) (x - 13) = 0

, so

x = 12

or 13. II:

(y - 5) (y - 8) = 0

, so

y = 5

or 8. Every

x

is bigger than every

y

, so

x > y

.

Answer: C)

x > y

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