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Find how $x$ and $y$ compare, given I. $x^{2} - 2 x - 15 = 0$
II. $y^{2} - 15 y + 56 = 0$ .

Competition practiceQuadratic Comparison

A $x > y$
B $x$ ≥ $y$
C $x < y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(x - 5) (x + 3) = 0

, so

x = 5

or −3. II:

(y - 7) (y - 8) = 0

, so

y = 7

or 8. The largest

x

(5) is below the smallest

y

(7), so

x < y

.

Answer: C)

x < y

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