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Compare the roots of I. $2 x^{2} - 7 x + 6 = 0$
II. $4 y^{2} - 12 y + 9 = 0$ .

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x < y$
C $x > y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(2 x - 3) (x - 2) = 0

, so

x = 1.5

or 2. II:

(2 y - 3)^{2} = 0

, so

y = 1.5

. Every

x

is at least 1.5, so

x

≥

y

.

Answer: A)

x

≥

y

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