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Given I. $x^{2} + 3 x - 10 = 0$
II. $y^{2} - 7 y + 12 = 0$ , what is the relation between $x$ and $y$ ?

Competition practiceQuadratic Comparison

A $x < y$
B $x > y$
C $x$ ≤ $y$
Drelation cannot be established

Step-by-Step Solution

I:

(x + 5) (x - 2) = 0

, so

x = - 5

or 2. II:

(y - 3) (y - 4) = 0

, so

y = 3

or 4. Every

x

is smaller than every

y

, so

x < y

.

Answer: A)

x < y

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