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I. $x^{2} - 16 = 0$
II. $y^{2} - 8 y + 16 = 0$ . Choose the correct relationship between $x$ and $y$ .

Competition practiceQuadratic Comparison

A $x > y$
B $x < y$
C $x$ ≥ $y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

x = 4

or −4. II:

(y - 4)^{2} = 0

, so

y = 4

only.

x = 4

gives

x = y

and

x = - 4

gives

x < y

, so

x

≤

y

.

Answer: D)

x

≤

y

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