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I. $x^{2} + 3 x - 10 = 0$
II. $y^{2} - 5 y + 6 = 0$ . Solve both and state the relation between $x$ and $y$ .

Competition practiceQuadratic Comparison

A $x > y$
B $x$ ≥ $y$
C $x < y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(x + 5) (x - 2) = 0

→

x = 2

, −5. II:

y = 2

, 3. The largest

x

equals the smallest

y

(2), so

x

≤

y

.

Answer: D)

x

≤

y

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