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In the following two equations, find the relationship between $x$ and $y$ . I. $x^{2} - 8 x + 15 = 0$
II. $y^{2} - 15 y + 54 = 0$

Competition practiceQuadratic Comparison

A $x < y$
B $x > y$
C $x$ ≥ $y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(x - 3) (x - 5) = 0

→

x = 3

, 5. II:

(y - 6) (y - 9) = 0

→

y = 6

, 9. Every

x

is strictly less than every

y

, so

x < y

.

Answer: A)

x < y

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