Solve both equations and choose the relation that always holds. I. $x^{2} - 45 x + 506 = 0$
II. $y^{2} - 52 y + 667 = 0$

Question

Solve both equations and choose the relation that always holds. I. x² − 45x + 506 = 0 II. y² − 52y + 667 = 0

Accepted Answer

x ≤ y. I: (x−22)(x−23) → x = 22, 23. II: (y−23)(y−29) → y = 23, 29. The largest x (23) only matches the smallest y (23) and never passes it, so x ≤ y.

Solve both equations and choose the relation that always holds. I. $x^{2} - 45 x + 506 = 0$
II. $y^{2} - 52 y + 667 = 0$

Step-by-Step Solution

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More Quadratic Comparison practice

Solve both equations and choose the relation that always holds. I. x2−45x+506=0II. y2−52y+667=0

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Quadratic Comparison practice

Solve both equations and choose the relation that always holds. I. $x^{2} - 45 x + 506 = 0$
II. $y^{2} - 52 y + 667 = 0$